Force

A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

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Be the first to comment - What do you think?  Posted by Mathew Abraham - September 11, 2011 at 3:02 pm

Categories: Ask Physics, brakes, Force, Mechanics, Project   Tags: , , , , , , , , , , , ,

A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

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Be the first to comment - What do you think?  Posted by Mathew Abraham - at 3:02 pm

Categories: Ask Physics, brakes, Force, Mechanics, Project   Tags: , , , , , , , , , , , ,

Numerical Problem from Friction

“The friction coefficient between a road and the tyre of a vehicle is 4/3.find the maximum incline the road may have so that once hard brakes are applied and the wheel starts skidding,the vehicle going down at a speed of 10m/s is stopped within 5m”...

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Be the first to comment - What do you think?  Posted by Mathew Abraham - September 10, 2011 at 11:16 am

Categories: Ask Physics, banking, brakes, Force, friction coefficient, friction forces, Mechanics, Project, roads, skidding, tyre, wheel   Tags: , , , , , , , , , , , ,

Numerical Problem from Motion of Connected systems

Two blocks A and B of mass m1 and m2 respectively are kept in contact on a frictionless table.The experimenter pushes the block A from behind so that the blocks accelerate. If  the block A exerts a force F on the block B,what is the force exerted by the experimenter on A. Incoming search terms:numericals on [...]

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Be the first to comment - What do you think?  Posted by Mathew Abraham - at 11:10 am

Categories: Ask Physics, Connected, connected systems, experimenter, Force, m1, m2, Mechanics, Project   Tags: , , , , , , , , ,

Solution to HC Verma Problem

“Referring to HC Verma Part 2, chapter 29, Electric field and potential, Q 69 I think that Force is inversely proportional to square of the distance between the charged particles, so acceleration is not constant and hence v*v  =  u*u  + 2*a*s   is not valid in this case. [...]

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Be the first to comment - What do you think?  Posted by Mathew Abraham - at 11:07 am

Categories: Ask Physics, concept, Electronics, Force, HC VERMA, Physics Links, Project, satyam, v 160   Tags: , , , , , , , , , , , , , , , ,

Solving problems from kinematics and friction

I just want to know how to easily solve problems related to kinematics and friction. I don’t know why i always face problem in these two topics a lot…… Please help and tell some tricks to solve these both……. THANK U Incoming search terms:class x physics kinematics numericalsfriction physics problemshow to [...]

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Be the first to comment - What do you think?  Posted by Mathew Abraham - at 11:03 am

Categories: Ask Physics, Force, KINEMATICS, lot, Project, solving problems, THANK   Tags: , , , , , , , , , , ,

Pseudo force and solving problems

Sir,can we solve problem without considering pseudo forces in non inertial frame?(give an example) Incoming search terms:QUESTINS FOR PROPERTIES OF MATTERoverloading physicsa stary nightsample paper of 10 class sa 1resultant force due to magnetic effectscience sample paper for class 2011 sa1sample question for cbse class ix sa1star and nightmagnetic forces onlyfree download of cbse based social [...]

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Be the first to comment - What do you think?  Posted by Mathew Abraham - September 7, 2011 at 4:00 pm

Categories: Ask Physics, Force, frame, inertial, inertial frame, Project, Sir, solving problems   Tags: , , , , , , , , , , , ,

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