Category Archive: Mechanics

Nov 06

A Video on Archimedes Principle.

Archimedes

Bust of Archimedes

Principle states that whenever a body is partially or completely immersed in a liquid it experiences an outward force (called buayant force or upthrust) which is equal to the weight of

read more

Permanent link to this article: http://www.plustwophysics.com/a-video-on-archimedes-principle/

Jun 18

Relative Nature of Motion

Now we know that motion is a relative term.So absolute motion has no meaning, right? So aren’t Galileo’s view that earth moves around sun and the church’s old belief that sun moves around

read more

Permanent link to this article: http://www.plustwophysics.com/relative-nature-of-motion/

Sep 13

The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=15m/s a=-10m/s2 v=0 m/s [...]

Permanent link to this article: http://www.plustwophysics.com/the-problem-of-a-rock-thrown-vertically-up-3/

Sep 13

The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...

Permanent link to this article: http://www.plustwophysics.com/the-problem-of-a-rock-thrown-vertically-up-2/

Sep 13

The problem of a rock thrown vertically up

A rock is thrown vertically upward from the ground with an initial speed 15m/s. a. how high does it go b. how much time is required for the rock to reach its maximum height? c. what is the rock’s height at t=2.00s? (Posted by Merhawi) Answer: (a) u=1...

Permanent link to this article: http://www.plustwophysics.com/the-problem-of-a-rock-thrown-vertically-up/

Sep 11

A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

Permanent link to this article: http://www.plustwophysics.com/a-simple-numerical-on-momentum/

Sep 11

A simple numerical on momentum

Car mass is 1200 kg moving velocity is 108 km/hr. On applying brakes velocity reduced to 36 km/hr. Find change in momentum? (posted by Aditi) Answer: m=1200 kg u=108 x 5/18=30m/s v=36×5/18=10m/s Change in momentum = m(v-u) = 1200 x (30-10)=1200 ...

Permanent link to this article: http://www.plustwophysics.com/a-simple-numerical-on-momentum-2/

Older posts «

%d bloggers like this: