A stone tied to a string of length l is whirled around a vertical circle with the other end of the string at the centre. At a certain instant of time the stone is at the lowest position and has a speed u. What is the magnitude of change in its velocity as it reaches a position where the string is horizontal?
Let’s assume that the potential energy at the lowest position be zero. So, when the string is horizontal, the stone has risen by a vertical height l, the length of the string which is also the radius of the vertical circle.
If v is the magnitude of velocity at the horizontal position, then according to the law of conservation of energy,
KE+PE at the lowest position = KE+PE at the horizontal position
From the equation above, v-u can be calculated.
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A short is fired from a gun on the top of a hill 90m high with velocity 80m/s at an angle of 30 degree with the horizontal. Find the horizontal distance between the vertical line through the gun and the ponit where the shot strikes the ground? (Shilpa asked this question)
Take Sy= -90m
uy= u sin(30) =80 x 0.5 = 40m/s
Substitute in the eqn
s = ut + 0.5 at2
and find t
The horizontal distance Rx = horizontal velocity x time = U cos (30) x time
Substitute for u and t and get the answer
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Devender posted this question: A plane is flying horizontally at 98m/s and releases an object, which reaches the ground in 10s. the angle made by it while hitting the ground is
(a) 55 degree
(b) 45 degree
(c) 60 degree
(d) 75 degree
A bullet of mass 20g enters into a fixed block with aspeed 40m/s and stops in it. find the change in internal energy during the process.
A bullet of mass 20 g enters into a fixed block with a speed 40m/s and stops in it.
find the change in internal energy during the process?
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