## CBSE Results – Students worried over delay in results

CBSE has not yet declared the results though the other boards have declared and admission process to the next level started in most states. Students started expressing their worries in social networks.

## Solving problems from kinematics and friction

I just want to know how to easily solve problems related to kinematics and friction. I don’t know why i always face problem in these two topics a lot…… Please help and tell some tricks to solve these both……. THANK U Incoming search terms:class x physics kinematics numericalsfriction physics problemshow to [...]

## Kinematics Problem

In a circus show a clown who is sitting on a post with height,H drops an apple to the ground.At the same time another clown throw an orange vertically upward from ground with speed 11 m/s.If both fruits pass each other after 0.8s, (a) determine the height (b) where do the apple and orange meet? [...]

## KERALA PLUS TWO PHYSICS SAMPLE QUESTION PAPER

The following links to SCERT will help you get a handful of good sample papers for preparation for Plustwo Physics Exams including the Onam Examinations

Class X Physics Sample Paper (SSLC) 2006

## KVS Announces Exam Dates for SA II for IX and X and Annual exam for Class XI

Date Sheet for SA-II Class IX-2010-2011

 Date IX (School Level SA-II) 03.03.2011 Thursday ………. 04.03.2011 Friday Social Science 05.03.2011 Saturday …………… 07.03.2011 Monday …………… 08.03.2011 Tuesday Maths 09.03.2011 Wednesday …………… 10.03.2011 Thursday Sanskrit 11.03.2011 Friday …………… 14.3.2011 Monday …………… 15.03.2011 Tuesday Science 16.03.2011 Wednesday …………… 17.03.2011 Thursday English 18.03.2011 Friday …………… 21.03.2011 Monday Hindi

EXAMINATION TIMING;

(i)         09.00 AM to 12.00 Noon

(ii)               15 minutes extra time is to be provided to the

## A problem from light for class X

Sudhanshu Misra posted:

“An object is placed at a distance of 10cm from convex mirror of focal length15cm; find the position and nature of image?”

Ans:

f= 15 cm

u=-10 cm

v=?

substitute the values